How do I delete the spacing between $\lambda_{A}$ and the parenthesis in the equation below?
$$\lambda_{A}\left(\bigcup\limits_{i=s}^{t} S_i\right)$$
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2$\begingroup$ You could try putting \! between the two. $\endgroup$– Gerry MyersonCommented Jun 1, 2020 at 3:50
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3$\begingroup$ I really don't see a problem in the formatting you display in your question. $\endgroup$– amWhyCommented Jun 1, 2020 at 16:07
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2 Answers
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The best way to do it is to use \mathop to make $\rm\LaTeX$ think that this is an operator:
$$\mathop{\lambda_A}\left(\bigcup_{i=s}^t S_i\right)\\\lambda_A\left(\bigcup_{i=s}^tS_i\right)$$
(There are also \mathbin and \mathrel for binary operators and relations respectively.)
answered Jun 1, 2020 at 8:48
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As @GerryMyerson mentions in the comments, you can use the negative space command \!. You can even apply multiple of them if one doesn't have enough effect; the equations below have 0 up to 3 \! instances.
$$\lambda_{A}\left(\bigcup\limits_{i=s}^{t} S_i\right)$$ $$\lambda_{A}\!\left(\bigcup\limits_{i=s}^{t} S_i\right)$$ $$\lambda_{A}\!\!\left(\bigcup\limits_{i=s}^{t} S_i\right)$$ $$\lambda_{A}\!\!\!\left(\bigcup\limits_{i=s}^{t} S_i\right)$$
It's even possible to apply so many negative spaces that $\lambda_A$ ends up at the right side of the equation:
$$\lambda_{A}\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\left(\bigcup\limits_{i=s}^{t} S_i\right)$$
(but of course there is a much easier way to do so).
