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In the comment to this answer: https://math.stackexchange.com/a/144819/21919

the last display formula shows $...-f(x\,0)$ instead of $\ldots-f(x_0)$, though it is not a misprint. I tried to edit it, and to post the whole comment anew, but this little bug persists. It shows in Chrome (version 27.0.1453.116 m) and IE 8 under Windows 7.

Here's my original TeX code:

Nice! However, I had hard time understanding the last sentence, so maybe it is worth to supply a few more details as follows: Let $V$ denote the variation over the partition chosen within $\epsilon/2$ of $TV(f_{[x_1,x_0]})$ as described above. Then $$TV(f_{[x_1,x_0]})< V+\epsilon/2.$$ Also, $V-|f(x)-f(x_0)|$ is some variation over interval $[x_1,x]$, so we have: $$TV(f_{[x_1,x]})\ge V-|f(x)-f(x_0)|.$$ Finally, $TV(f_{[x_1,x_0]})=TV(f_{[x_1,x]})+TV(f_{[x,x_0]})$, so that: $$TV(f_{[x,x_0]})=TV(f_{[x_1,x_0]})-TV(f_{[x_1,x]})<(V+\epsilon/2)-(V-|f(x)-f(x_0)|)<\epsilon/2+\epsilon/2=\epsilon.$$

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This answer addresses the same problem. It is best to insert a space every so often into MathJax in a comment so that there are not 80 characters unbroken by spaces.

In the comment in consideration,

$$TV(f_{[x,x_0]})=TV(f_{[x_1,x_0]})-TV(f_{[x_1,x]})<(V+\epsilon/2)-(V-|f(x)-f(x_

is 80 characters. The two unicode spaces are inserted between the underscore and the zero, interrupting the MathJax.

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  • $\begingroup$ Thanks! This really explains it! $\endgroup$ – mathreader Jul 10 '13 at 7:14

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