12
$\begingroup$

There are 74 accounts belonging to the emailhash b60d6b835a36491ae1fddecd1265894d (with a notable overall score). Does this really indicate that they belong to the same person resp. email address?

Would it make sense to merge these accounts for better traceability?

EDIT @mrf: Here's the full list...

$\endgroup$
2
  • 4
    $\begingroup$ I assume you didn't find these by searching for random hashes? $\endgroup$
    – mrf
    Commented Sep 13, 2013 at 22:21
  • $\begingroup$ @mrf unfortunately I removed my query to prove it, but 'b60d6b835a36491ae1fddecd1265894d' was just one example... $\endgroup$
    – draks ...
    Commented Sep 14, 2013 at 9:09

1 Answer 1

16
$\begingroup$

From a sample of several of these accounts, they do all appear to be the same user, who has not registered an account and seems to clear their cookies between each visit to the site.

It would make sense to merge them. However, moderators can no longer merge users; it must be done either by the user themselves or the StackExchange team. Since there does not appear to be any malicious or rule-breaking activity coming from these users, I see no reason to bother the team with merging them.

$\endgroup$
4
  • $\begingroup$ Why can't moderators no longer merge users? Is there a reason? $\endgroup$
    – draks ...
    Commented Sep 14, 2013 at 11:47
  • 4
    $\begingroup$ @draks... Merging is a rather dangerous operation, and if you're wrong then you are granting access to the account to a completely unrelated person, which is a rather big privacy issue. $\endgroup$
    – user9733
    Commented Sep 14, 2013 at 15:17
  • 5
    $\begingroup$ Is it not possible that this (or any similar) user has a reason for not wanting their unregistered accounts merged? Unless that reason is malicious I feel we should respect such a users intentions. $\endgroup$
    – Dan Rust
    Commented Sep 15, 2013 at 12:10
  • 3
    $\begingroup$ Maybe it's some dummy email address like "[email protected]" $\endgroup$ Commented Sep 17, 2013 at 22:00

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .