I wonder whether unchecking an answer causes some loss of reputation to the answerer.

A user that I hold in great esteem for his skills as a brilliant mathematician and a clear and patient teacher has asked me to uncheck one of his answers in order to give the question more evidence and opportunities to get an answer even more detailed than his, but I do not want to damage him in any way. I think that losing reputation is a damage because, by losing reputation, one loses opportunities to start bounties.

Does unchecking an answer cause a loss of "rep"? I thank you for any answer!

• Really you should not worry about this, in general and even less if they asked you so. Chances are they have more points than they ever want to use for bounties regardless. And, in any case, I think you should honor their request.
– quid Mod
Nov 7 '14 at 17:09
• Hi Davide, sorry for off-topically pinging you here, I have stopped being active on Physics SE (you can read why on my profile there). Technical questions containing LaTex that involve derivations, calculations, etc you better ask on PhysicsForums or Quora where they are better received. Math SE is an ok place for them too, but most physicists dont answer things on Math SE ... Feb 14 '16 at 12:55
• @Dilaton I heartily thank you! I have asked this on Quora. Thank you for suggesting PhysicsForums too! Feb 14 '16 at 13:11
• @Dilaton My last question on PSE has been migrated here. I hope I will never see comments scoffing at me because I'm convinced that $(\mathbf{l},r_i)\mapsto\frac{\mathbf{J}(\mathbf{l})\times(\mathbf{r}-\mathbf{l})}{\|\mathbf{r}-\mathbf{l}\|^3}$, with $\mathbf{r}=\sum_{i=1}^3 r_i \hat{\mathbf{e}}_i$, isn't continuous at the points where $\mathbf{r}=\mathbf{l}$, like this, at least not here... Feb 14 '16 at 20:41
• and also notice that the scoffing user, also a down/close voter, also is the person that suggested me to ask the question about the single steps I don't understand. Feb 14 '16 at 20:58
• @Self-teachingDavide yes I know him ... ;-). To me it seems $I$ is not continuous indeed for $r=l$ indeed. Math SE is certainly a friendlier place for your question. Feb 14 '16 at 23:01