3
$\begingroup$

Lately I had a case that one of my questions was marked "as an exact duplicate".

Projection, rotation and skew-symetry in N-dimensional space

Commutativity of projection and rotation

But what the idea of "exactness" means regarding to questions? The subjects of both questions were evidently different, and even if they were really set in similar context, the two additional steps were required to go from one solution to the other - what was admitted by one of advocates for duplicativness.

Maybe the number of steps would be a good metrics for measuring distance between questions?
How can be measured distance between two questions in any other way?

$\endgroup$
5
  • 2
    $\begingroup$ Related: meta.math.stackexchange.com/questions/18917/… $\endgroup$
    – quid Mod
    May 17, 2016 at 12:28
  • $\begingroup$ Note also the dedicated thread for Requesting Reopening of Questions, etc.. Possibly the inclusion of words "skew symmetric" in your title would have discouraged some of those who voted to close as duplicate. $\endgroup$
    – hardmath
    May 17, 2016 at 16:38
  • $\begingroup$ @hardmath So I included them. All problem triggered my contemplation about the general nature of mathematical questions. Maybe the class of "exact duplicate" is too narrow ? If labels of "approximate duplicate" and "question with tendency for duplication" were introduced the projected metrics on questions would be more objective. $\endgroup$
    – Widawensen
    May 20, 2016 at 10:44
  • 1
    $\begingroup$ By editing the Question's title you've suggested to me that you are still interested in an answer there. In any case I've voted to reopen. $\endgroup$
    – hardmath
    May 20, 2016 at 13:12
  • $\begingroup$ @hardmath Of course question wasn't answered for all cases. Can be skew-symetric matrix decomposed somehow in higher dimensions involving rotation ? I don't know. Maybe it is possible but only for skew-symetric matrices with 3 DOF. $\endgroup$
    – Widawensen
    May 20, 2016 at 16:13

0

You must log in to answer this question.

Browse other questions tagged .