# $\LaTeX$ Symbol for a right-angled triangle [closed]

Is there a $\LaTeX$ symbol for a right-angled triangle, with the triangle lying on its right angle, either on the left or right?

There is $\triangle$, $\triangledown$, $\triangleleft$, $\triangleright$ but no right-angled triangle.

Any help would be appreciated. If there is none, perhaps some pointers on how to construct one. Thanks.

## closed as off-topic by Matt Samuel, Shailesh, suomynonA, Watson, Alex M.Oct 31 '16 at 9:57

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• I don't know, but I know there's a tex.stackexchange.com. – Gerry Myerson Oct 30 '16 at 5:14
• tex.stackexchange.com/questions/65455/… – davidlowryduda Oct 30 '16 at 5:24
• Thanks for your input, Gerry and mixedmath. The link was very helpful, @mixedmath – hypergeometric Oct 30 '16 at 7:53
• I used a picture environment. Unfortunately, answers are closed. Hopefully this will paste right. \begin{picture}(7,7) \put(1,6){\line(1,0){5}} \put(1,6){\line(0,-1){5}} \put(1,1){\line(1,1){5}} \end{picture} If the diagonal line doesn't print, you may need to add a \usepackage{pict2e} to the preamble. – johnnyb Jun 17 '18 at 17:42

In the "Mathematical Operators" section, we have

\unicode{0x22BF}$=\unicode{0x22BF}$ (RIGHT TRIANGLE)

As pointed out by hypergeometric, in the "Geometric Shapes" section, we also have

\unicode{0x25FA}$=\unicode{0x25FA}$ (LOWER LEFT TRIANGLE)
\unicode{0x25FF}$=\unicode{0x25FF}$ (LOWER RIGHT TRIANGLE)

• Thanks! That was very helpful! (+1) – hypergeometric Oct 30 '16 at 13:15

Posting this as a note to myself.

\unicode{0x25FA}: $\qquad\unicode{0x25FA}$

\unicode {0x22BF}: $\qquad\unicode {0x22BF}$

• So ... \unicode is recognized by Mathjax, but not by LaTeX. – GEdgar Oct 30 '16 at 13:39
• It appears so. Had to change (...) to {...}. – hypergeometric Oct 30 '16 at 13:39
• (+1) I don't know how the parentheses crept into my answer. I thought I had simply copied the LaTeX, but I guess in removing the backslashes, I made more of a change than I thought. I didn't see 0x25FA. In the Unicode table, it looks a lot smaller. Good catch! – robjohn Oct 30 '16 at 17:09
• @robjohn - Thanks for pointing out the crucial step! – hypergeometric Oct 30 '16 at 17:12