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I want to try my luck and see if someone can answer this question I made about a month ago: Simplifying the summation $ (3^i\sqrt{n/3^i})/\log_2(n/3^i)$ from $i=0 \text{ to }k-1$

I thought maybe a good way to draw attention to the question would be by starting a bounty, but I came to the realization that I cannot longer do this. Is there a way to make the option be available again?

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Yes, of course. But you need to have 75 points of reputation in order to set up a bounty.

So you're one vote away from that goal.

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  • $\begingroup$ Oh that explains everything lol, thanks for the information. $\endgroup$ – MikeKatz45 Mar 13 at 23:06
  • $\begingroup$ I know it's meta, but I just wanted to let you know I downvoted the answer by accident. $\endgroup$ – Matt Samuel Mar 14 at 19:30

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