How can I write backslash in MathJax?

Question

I want to write following in MathJax:

L(A)\L(B)

When I type following:

$L(A)\ L(B)$

It prints: $L(A)\ L(B)$

When I type following:

$L(A)\\ L(B)$

It prints: $L(A)\\ L(B)$

How can I make \ appear in MathJax?

Answer 1

If you want a real backslash, and not something spaced like a binary operation, use L(A)\backslash L(B) to get $$ L(A) \backslash L(B) $$

Answer 2

Use \setminus for the result $𝐿(𝐴)\setminus𝐿(𝐵)$.

Answer 3

Here's a list of possible solutions that I could come up with (includes a curated Detexify output), the first two are the other two current answers:

1. $L(A)\backslash L(B)$ $L(A)\backslash L(B)$
2. $L(A)\setminus L(B)$$L(A)\setminus L(B)$ (looks the same as the next too)
3. $L(A)\mathbin{\setminus}L(B)$ $L(A)\mathbin{\backslash}L(B)$
4. $ L(A)⧵L(B)$ $ L(A)⧵L(B)$using U+29F5 "Reverse Solidus Operator"
5. $L(A)\text{\ }\!L(B)$ $L(A)\text{\ }\!L(B)$ PS / also works in \text
6. $L(A)$\ $\!L(A)$ $L(A)$\ $\!L(A)$ (broken into two MathJax pieces) and similarly
7. $L(A)$ \ $L(A)$ $L(A)$ \ $L(A)$
8. $L(A) \diagdown L(B)$ $A \diagdown B$
9. $L(A)╲L(B)$ $L(A)╲L(B)$ using U+2572 "Box Drawings Light Diagonal Upper Left to Lower Right"
10. $L(A) \smallsetminus L(B)$ $A \smallsetminus B$
11. $L(A)﹨L(B)$ $L(A)﹨L(B)$ using U+FE68 "Small Reverse Solidus"
12. $L(A)＼L(B)$ $L(A)＼L(B)$ using U+FF3C "Fullwidth Reverse Solidus"
13. $L(A)\backprime L(B)$ $L(A)\backprime L(B)$
14. $L(A)\searrow L(B)$ $L(A)\searrow L(B)$

Answer 4

For fun:

How can I make \ appear in MathJax?

The command \cancel produces a forward slash: $\require{cancel}\cancel{\phantom{k}}$. A simple rotation flips it around to produce a backslash. So

\require{cancel}

L(A)\!\!\! 

\style{display: inline-block; transform: rotate(90deg)}{\cancel{\phantom{mm}}}

\!\!\! L(B)

gives

$$\require{cancel}L(A)\!\!\! \style{display: inline-block; transform: rotate(90deg)}{\cancel{\phantom{mm}}}\!\!\! L(B).$$

_{This is clearly easier better than \setminus or \backslash :P}