This is what I want. Can you please help me?

        \frac{x^3}{x^2+y^2} & (x,y)\ne(0,0), \\
        0 & (x,y)=(0,0).

$f(x,y)= \begin{cases} \frac{x^3}{x^2+y^2} & (x,y)\ne(0,0), \\ 0 & (x,y)=(0,0). \end{cases} $

See also: the corresponding answer in the MathJax basic tutorial and quick reference.

  • $\begingroup$ Maybe add "\displaystyle" before the "\frac"? $\endgroup$ – Barry Cipra Apr 16 '20 at 17:08
  • 2
    $\begingroup$ Or \dfrac. That's all probably matter of taste. (Not really the heart of the matter here, the OP asked mainly about the "cases" part.) $\endgroup$ – Martin Sleziak Apr 16 '20 at 17:10

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