I can't find how to write roots other than square root using MathJax. There doesn't seem to be anything about it on the legendary MathJax basic tutorial and quick reference
These are my best attempts, but they don't look right:
3\sqrt{64} $\rightarrow\text{ } 3\sqrt{64}$
{3}\sqrt{64} $\rightarrow\text{ } {3}\sqrt{64}$
^3\sqrt{64} $\rightarrow\text{ } ^3\sqrt{64}$
What I want to display:
How can I properly format it using MathJax? Or is it not possible in MathJax yet?
Use \sqrt[n]{m} to get the $n$th root of m: $\sqrt[n]{m}.$
$\root{a}\of{x}$ $\root{a}\of{x}$ yes that works too! Thanks
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Oct 16, 2020 at 17:47
$$\sqrt[3]{64}$$
produces
$$\sqrt[3]{64}$$
This is standard LaTeX syntax, see e.g. this page. It might be confusing since 'sqrt' is an abbreviation of 'square root', but it works nevertheless.
\sqrt[3]{64}gives you $$\sqrt[3]{64}$$ $\endgroup$\sqrt[n]m$\sqrt[n]m$ didn't exist you would add negative space to get some approximation of the real deal{}^3\!\!\!\sqrt{64}${}^3\!\!\!\sqrt{64}$ also note that you need{}^3instead of just^3to avoid the previous thing from having a power e.g.a=^3\sqrt bvsa={}^3\sqrt b$a=^3\sqrt b$ vs $a={}^3\sqrt b$. In fact if the previous thing already has a power then you get an error e.g.a^3^3\sqrt bvsa^3{}^3\sqrt b$a^3^3\sqrt b $ vs $a^3{}^3\sqrt b$. This is useful if you like writing $a_{ij}{}^{kl}$, ${}^t\!A$, ${}^n C_r$... $\endgroup$