# Why did 2 users reject my suggested edit for 2 typos? How can $P(M_2, C_2) + P(M_2, C_2) = 0 + 1/3$?

pls see below picture, and https://math.stackexchange.com/review/suggested-edits/1725174. $$P(M_2, C_2)$$ can't equal both 0 and 1/3. something is wrong!

• Your edit description could have been more descriptive, I guess Jan 1 at 6:55
• Shouldn't the third summand actually be $P(M_2,C_3)$ and not $P(M_3,C_3$ as in your edit? Jan 1 at 11:02
• Also for the numerator: $P(car,M_2,C_3)$.
– JRN
Jan 1 at 11:07
• I see you left two comments for the author of that Answer, but neither specifically points out the "typos" you spotted. It can be difficult to know what to do when a user doesn't respond within a couple of days, but then the Question is ten months old, so I would not hurry things too much. The Monty Hall problem has been addressed many times on this site and elsewhere, so I'd not personally be motivated to do a careful revision of the longish Answer given there. Jan 1 at 15:55
• @CalvinKhor Sorry about misunderstanding. I meant...I know some people like to follow up in comments. But editing answer is better because comments can be deleted or moved to chat! Obvious now? I did not point to other typos. See above comments here. Jan 3 at 6:53
• The above comments are saying that you introduced a typo. There remains only one typo that I am aware of (but I did not read the answer closely) Jan 5 at 5:45
• @CalvinKhor see my edited post. Jan 5 at 5:51
• Since the picture in the question changed, i link to the old one which shows that the numerator was changed (wrongly cf Martin's comment) - i.stack.imgur.com/UoyKA.jpg Jan 6 at 6:41