Polyhedron of maximum Volume & given frame length

After deleting some answers leading up to this post my answer is found masked on mouse pointer hover.

The much upvoted question I found to be very interesting but needed to be researched before answer. My reply todate stands as the only reply.

After each improvement in the volume indicator updates with increased clarity is posted after deleting earlier one.. I may still improve it if possible.

Can anyone please help indicate what causes the masking?

Thanks for a clue.

  • 7
    $\begingroup$ if I understand you correctly; your answer is greyed out as it has a sufficiently negative score (I think it was ≤-3) $\endgroup$ Nov 8 at 11:28
  • 8
    $\begingroup$ "After each improvement in the volume indicator updates with increased clarity is posted after deleting earlier one.." I have no idea what this means. I note that your grayed-out answer is currently in its 18th version. This is never a good sign. $\endgroup$ Nov 8 at 12:35
  • 1
    $\begingroup$ I see it as greyed-out (for the low net negative score, I assume), but when I hover my pointer over the body it gets un-greyed. $\endgroup$ Nov 8 at 16:28
  • $\begingroup$ @ Dear Professor Gerry Myerson: Attempt was made for construction of a new polyhedron with maximum enclosed volume as $$\frac {\Sigma V}{(\Sigma L=1)} ,$$ This parameter is referred to also as volume indicator or volume for total edge/frame length... I continued the method suggested by OP for improving the parameter so that others may improve on it after seeing the method adopted or in some other better way as sharing in the work especially as there was not a single other response. $\endgroup$
    – Narasimham
    Nov 8 at 19:38
  • $\begingroup$ contd... the deleted answer were not cancelled as incorrect but as a better one was found every time after working on it subsequently. I suppose anyone should not be made to feel sorry for a desire to share with others. $\endgroup$
    – Narasimham
    Nov 8 at 19:39
  • 4
    $\begingroup$ The at-sign doesn't work the way you think it does, Narasimham. In order to notify someone, the at-sign has to be followed immediately by the name of the user you want to notify, with no intervening spaces or words like "Dear Professor". (and how do you divide a number by an equation? and why is the equation in parentheses?) $\endgroup$ Nov 8 at 21:38
  • $\begingroup$ Okay, thanks @GerryMyerson. Unless I missed something, it looked standard replacement computation to me. Many CASs do not treat the denominator with parentheses enclosing symbols as an equation. When (A,a) are constants for instance A/(a=1) simply returns A. To be sure I checked on Mathematica. $\endgroup$
    – Narasimham
    Nov 10 at 20:08
  • 4
    $\begingroup$ OK. math.stackexchange is not a CAS, so I treat mathematical expressions as mathematical expressions. $\endgroup$ Nov 10 at 20:59
  • $\begingroup$ OK sir, small matter.. since the same fraction is copied here I thought the reader who read my post already would immediately recognize it. Regards $\endgroup$
    – Narasimham
    Nov 10 at 22:51
  • $\begingroup$ Why then would one write $A/(a=1)$ when you can just write $A$? $\endgroup$ Nov 11 at 4:12
  • $\begingroup$ $\frac {\Sigma V}{\Sigma L}=\frac {\Sigma V}{1}$ could be better without shorthand ... in the now deleted post. $\endgroup$
    – Narasimham
    Nov 12 at 19:37
  • $\begingroup$ @Narasimham Please read this meta post about the question. $\endgroup$
    – amWhy
    Nov 19 at 22:29
  • $\begingroup$ Thanks @amWhy. There have been my errors, rightly was pointed out ; I am still working on the very interesting problem as it touches on my area of familiarity. Is there any related particular matter you wish to draw my attention ? Regards $\endgroup$
    – Narasimham
    Nov 19 at 23:05


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