2 days ago I posted this question:
Suppose we have
$F(z)=f(\phi(z))$ where $\phi$ is a mobius transformation which maps points of the unit circle to points of the unit circle. Suppose also that there is an interval of length $\pi$ such that on that interval $f(e^{it})-f(e^{-it})>0$. How to prove then this is also true for $F$?
Here, I defined:
$\phi(z):=\frac{z_0-z}{1-\bar{z_0}z}$ with $z_0$ a fixed point of the unit disk (without the boundary) and $f$ a real harmonic continuous function defined on the unit disk. And $F(z)=f(\phi(z))$.
I had a good answer, but now it has disappeared and I really need it. The person that answered (and then I think I said: "a really big thank you!"), can you repeat your answer please? I would be very thankful