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I recently found this question: Proof of the Existence of All Phone Numbers in Pi

I understand why it can be seen as a duplicate of Does π contain all possible number combinations?, but the question is much more specific and there is a proof that doesn't need π to be a normal number: a proof by exhaustion.

As discussed in my comment, since the early 2000s, we know enough digits of π to prove that it contains all 10-digit number sequences with an exhaustive search. However, this proof wouldn't make sense as an answer to the question on all possible number combinations.

Related question: Should questions about special cases of a more general problem be marked (closed) as duplicate?

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    $\begingroup$ No. The question on all possible number combinations has no answer to the question on all phone numbers, so “This question already has answers here” is wrong. If there was a proof that pi is normal, then it answered the latter, but that is open. $\endgroup$
    – user1125430
    Commented Sep 1, 2023 at 3:33
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    $\begingroup$ I think you have a good point, but this meta question should really go into the Request for Reopen Votes thread: math.meta.stackexchange.com/questions/34447/…. $\endgroup$
    – MaoWao
    Commented Sep 1, 2023 at 7:30
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    $\begingroup$ @MaoWao Thanks for letting me know, I wasn't aware of that procedure. I've added it here: math.meta.stackexchange.com/a/35942/477462 $\endgroup$
    – DecimalTurn
    Commented Sep 1, 2023 at 18:56

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