I have noticed then when I first wish to tag someone in a comment with "@" upon typing say "g" choices come up like "gauss" or "galois" depending on which user is mentioned in the thread. However when I want to do a second tag not only do such choices not show up but a yellow box shows up saying

"Only one additional @user can be notified; the post owner will always be notified."

What is the reason for this? Thanks.

  • 4
    $\begingroup$ This is [status-declined] on meta.stackoverflow.com: Allow more than one @name notification per comment. $\endgroup$
    – user856
    Commented Feb 8, 2012 at 9:31
  • $\begingroup$ can you also tag someone you know after posting a new question that has not been answered yet? $\endgroup$
    – Ab2020
    Commented Feb 5, 2023 at 3:57

1 Answer 1


See Fabian's answer to your previous question for how @-notifications work.

To partially address Bill Dubuque's comment on Jeff's answer, and to make double clear to you that the second @ will not send a notification, Stack implemented a smart system to show you who you can notify and to tell you that you just can't notify more than one person per comment. This way you don't get disappointed when

  1. You spelled the user's name wrong, hence the user doesn't get the notification.
  2. You added a second @, and that user doesn't get the notification.

To repeat: a second @ notification has never been supported. Previously it just fails silently. Now at least it tells you that "hey buddy, that ain't gonna work."

  • $\begingroup$ It makes me wonder which was harder to code: implementing multiple notifications or that (annoying) popup message. :) $\endgroup$
    – cardinal
    Commented Feb 8, 2012 at 15:21
  • $\begingroup$ @cardinal I believe that restriction is 100% intentional, to limit users annoying too many people at once by notifying them in their global inboxes. $\endgroup$
    – user9733
    Commented Feb 8, 2012 at 16:50
  • $\begingroup$ @WillieWong So that would mean if I want to notify two people I have to post two comments. Thanks. $\endgroup$
    – user5783
    Commented Feb 8, 2012 at 23:19

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