I just edited: Let $f$ be a non-constant entire function such that $\left \lvert f(z) \right\lvert=1$ for every $z$ with $\left \lvert z \right\lvert=1$.

In the question there is a list of options numbered with (a) and (b) and so on. I wanted to put it in a nicer list, but how do you make an ordered list with letters instead of numbers?

If this is not possible, I would suggest that this be made possible.

Edit: I might not have been clear enough: When I edit I want to stay near to the original formatting and wording and change only what I think is needed. I have seen some questions lately where one has to choose between some options (a), (b), (c), and (d), and I just wanted to put that in a list like

  1. Option
  2. Option
  3. Option
  4. Option

with (a), (b), (c), (d) instead of 1,2,3,4. But the only way I can figure out how to do it is by making a bullet point list:

  • (a) Option
  • (b) Option
  • (c) Option
  • (d) Option

But I don't like the bullets. The question is whether there is a "pre-formatted" way to do this?

  • $\begingroup$ I don't understand. What happens if you just use 1, 2, 3, 4 where the problem has a, b, c, d? $\endgroup$ Dec 8, 2012 at 6:23
  • $\begingroup$ @Gerry: You have to show there is an order isomorphism between then list, and that's a whole other question... $\endgroup$
    – Asaf Karagila Mod
    Dec 8, 2012 at 13:03
  • $\begingroup$ @GerryMyerson: Well, obviously the universe would implode. $\endgroup$
    – Thomas
    Dec 8, 2012 at 17:00

1 Answer 1


I don't know whether there is a pre-formatted way, but does

$\quad$(a) Option
$\quad$(b) Option
$\quad$(c) Option
$\quad$(d) Option

look like what you want?

  • 1
    $\begingroup$ Yeah, that pretty much is it. I might add a future suggestion tag as well to see if it could be implemented a a nice way. Thanks though for experimenting. $\endgroup$
    – Thomas
    Dec 9, 2012 at 19:54

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