Mathematics
Тyma Gaidash٠'s user avatar
Тyma Gaidash٠'s user avatar
Тyma Gaidash٠'s user avatar
Тyma Gaidash٠
  • Member for 2 years, 6 months
  • Last seen this week
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About

Maybe “Tyma” stands for “The Yearning Math Aficionado”. Perhaps “Gaidash” stands for “Great at Inventing Desirable and Smart Hints”.

Together they make up Tyma Gaidash, the yearning math aficionado who is great at inventing desirable and smart hints.

It is just a hobby. I also teach on Gaidash.com

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Top posts
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All Questions Answers
Score Newest
question
9
Color change on the M.Se site.
Jul 20, 2021
question
4
Glitch Discovered During Downvote. I Gained the “Critic” Badge for Upvoting and then Downvoting my Own Question on my Own Account. Second Time.
May 10, 2021
question
3
What is the most upvoted comment?
Jul 27, 2021
question
2
A red low quality post. What does it mean? [duplicate]
Aug 17, 2021
question
1
Did the profile tags change size?
Oct 22, 2021
question
1
Stack exchange goes to different question than in URL
Sep 16
question
0
Community user new profile photo.
Jul 15, 2021
question
0
Bug with my gravatar?
Jul 19, 2021
question
0
A lot of upvotes in a single day?
Sep 14, 2021
question
0
Accidentally editing without knowing a question was closed in the review queue made a question unable to be reopened. New feature to prevent this.
May 15, 2021
Top network posts
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65
Evaluating $\sum\limits_{x=2}^\infty \frac{1}{!x}$ in exact form.
16
Integral over domain of infinite tetration of x over extended domain from 0 to $\sqrt[e]e$. Possible $\int_{e^{-e}}^{e^\frac1e} x^{x^{…}}dx$ solution.
15
Is there an exact solution for $\large\int \frac{dx}{\tan^{-1}(x)}$?
14
Why Dottie$=2\sqrt{I^{-1}_\frac12(\frac 12,\frac 32)-I^{-1}_\frac12(\frac 12,\frac 32)^2} = \sin^{-1}\big(1-2I^{-1}_\frac12(\frac 12,\frac 32)\big)$?
13
How to straighten a parabola?

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