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May 16, 2019 at 20:06 comment added Américo Tavares @Maria Mazur For the same example $ \dfrac{x^3-6x^2+11x-6}{x-1}=x^2-5x+6$: $$\begin{array}{rrrr|ll} x^3 & -6x^2 & +11x & -6 & x - 1 \\ -x^3 & +x^2 & & & x^2-5x+6 \\ \hline & -5x^2 & +11x & -6\\ & \phantom{-}5x^2 & -5x & & & & \\ \hline & & +6x & -6 \\ & & -6x & +6 \\ \hline & & 0 & 0 \end{array}$$ I've used this code \begin{array}{rrrr|ll} x^3 & -6x^2 & +11x & -6 & x - 1 \\ -x^3 & +x^2 & & & x^2-5x+6 \\ \hline & -5x^2 & +11x & -6\\ & \phantom{-}5x^2 & -5x & & & & \\ \hline & & +6x & -6 \\ & & -6x & +6 \\ \hline & & 0 & 0 \end{array}
May 23, 2017 at 12:39 history edited CommunityBot
replaced http://stackoverflow.com/ with https://stackoverflow.com/
Aug 21, 2016 at 14:32 comment added Américo Tavares Synthetic division. Example to find that $$x^3−6x^2+11x−6=(x−{\color{red}1})(x^2−5x+6)+{\color{blue}0}$$ \begin{array}{c|rrrr}& x^3 & x^2 & x^1 & x^0\\ & 1 & -6 & 11 & -6\\ {\color{red}1} & \downarrow & 1 & -5 & 6\\ \hline & 1 & -5 & 6 & |\phantom{-} {\color{blue}0} \end{array} \begin{array}{c|rrrr}& x^3 & x^2 & x^1 & x^0\\ & 1 & -6 & 11 & -6\\ {\color{red}1} & \downarrow & 1 & -5 & 6\\ \hline & 1 & -5 & 6 & |\phantom{-} {\color{blue}0} \end{array}
Jul 27, 2015 at 20:19 history edited MJD CC BY-SA 3.0
added 148 characters in body
Jul 27, 2015 at 19:35 history edited David K CC BY-SA 3.0
delete unused column specifiers of array
Jul 26, 2015 at 20:40 history rollback David K
Rollback to Revision 2
Jul 26, 2015 at 17:03 history edited David K CC BY-SA 3.0
received complaint that it doesn't work
Jul 26, 2015 at 16:10 history edited Najib Idrissi CC BY-SA 3.0
Fixed missing \require
S Jul 26, 2015 at 15:48 history answered David K CC BY-SA 3.0
S Jul 26, 2015 at 15:48 history made wiki Post Made Community Wiki by David K