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Jan 29 at 18:47 comment added hardmath I suspect that the problem statement has gotten a little garbled. There would seem no point in requiring $G$ (a subgroup of an abelian, even cyclic, group) to have order $6$ unless one was also meant to have $a,b,c$ mutually distinct and different from $1$.
Jan 28 at 20:36 history edited Gerry Myerson CC BY-SA 4.0
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Nov 25, 2023 at 20:59 history edited Gerry Myerson CC BY-SA 4.0
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Nov 18, 2023 at 12:36 history answered ShaunMod CC BY-SA 4.0