Long ago, I asked this question. It was never a duplicate of this one, since the question was pretty different, and when the question changed it still had a different viewpoint, yet it was closed as duplicate, and currently has only 2 reopen votes, including mine. I then asked an "exact duplicate", this one, to which Daniel answered in comments, and I just self-answered taking his comment and converting it to an answer. This question is to ask to reopen the first question to reclose it as the question it really is a duplicate of, i.e. the third one. And I ask because currently, if someone lands on the first question, he is redirected to a different question, which doesn't actually answer the first question, and so this person might not find an answer, well unless he reads the comments where I should have placed a link to question 3. If we reopen and reclose as a duplicate of question 3, the same person will find the answer. So can we do this?
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$\begingroup$ I'd just do this via a moderator flag with a less longwinded explication. "This (link) more recent questions is a much better dupe target than the current. Could you please change it?" $\endgroup$– quidCommented Feb 20, 2016 at 18:56
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$\begingroup$ @quid Whoops, didn't think of that. I only just started using flags and have them sort of associated with review items, since I only ever used them on posts I reviewed (or in one case on a question I reviewed a suggested edit to). Will keep that in mind. $\endgroup$– MickGCommented Feb 20, 2016 at 18:59
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4$\begingroup$ No problem. Another option would be to post in chat.stackexchange.com/rooms/20352/math-mods-office or chat.stackexchange.com/rooms/2165/c-r-u-d-e (in this case I'd go for the former). $\endgroup$– quidCommented Feb 20, 2016 at 19:01
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$\begingroup$ Did I get the reopening/reclosing right? If so, please remove the non-mathematical content from all these posts. They serve no useful role whatsoever. $\endgroup$– Jyrki Lahtonen ModCommented Feb 20, 2016 at 19:14
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$\begingroup$ @Jyrki yep, you got it right. $\endgroup$– MickGCommented Feb 20, 2016 at 19:16
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